1/3(18x+15)=1/4(4x=12)

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Solution for 1/3(18x+15)=1/4(4x=12) equation: 



1/3(18x+15)=1/4(4x=12)

We move all terms to the left:

1/3(18x+15)-(1/4(4x)=0



Domain of the equation: 3(18x+15)!=0

x∈R





Domain of the equation: 44x!=0

x!=0/44

x!=0

x∈R



We calculate fractions


44x/(2376x^2+1980x)+(-3x1/(2376x^2+1980x)=0



We calculate terms in parentheses: +(-3x1/(2376x^2+1980x), so:

-3x1/(2376x^2+1980x

We multiply all the terms by the denominator


-3x1

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

44x/(2376x^2+1980x)-3x=0

We multiply all the terms by the denominator


44x-3x*(2376x^2+1980x)=0

We multiply parentheses

-7128x^3-5940x^2+44x=0

We do not support expression: x^3

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