1/3(18x-6)=-5/6(12-6x)

Solution for 1/3(18x-6)=-5/6(12-6x) equation:

1/3(18x-6)=-5/6(12-6x)

We move all terms to the left:

1/3(18x-6)-(-5/6(12-6x))=0


Domain of the equation: 3(18x-6)!=0

x∈R



Domain of the equation: 6(12-6x))!=0

x∈R


We add all the numbers together, and all the variables

1/3(18x-6)-(-5/6(-6x+12))=0

We calculate fractions


(6x(-)/(3(18x-6)*6(-6x+12)))+(-(-15x1)/(3(18x-6)*6(-6x+12)))=0


We calculate terms in parentheses: +(6x(-)/(3(18x-6)*6(-6x+12))), so:

6x(-)/(3(18x-6)*6(-6x+12))

We add all the numbers together, and all the variables

6x0/(3(18x-6)*6(-6x+12))

We multiply all the terms by the denominator


6x0

We add all the numbers together, and all the variables

6x

Back to the equation:

+(6x)



We calculate terms in parentheses: +(-(-15x1)/(3(18x-6)*6(-6x+12))), so:

-(-15x1)/(3(18x-6)*6(-6x+12))

We add all the numbers together, and all the variables

-(-15x)/(3(18x-6)*6(-6x+12))

We multiply all the terms by the denominator


-(-15x)

We get rid of parentheses

15x

Back to the equation:

+(15x)


We add all the numbers together, and all the variables

21x=0

x=0/21

x=0