1/3(18y-6)=-5/6(12-4y)

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Solution for 1/3(18y-6)=-5/6(12-4y) equation: 



1/3(18y-6)=-5/6(12-4y)

We move all terms to the left:

1/3(18y-6)-(-5/6(12-4y))=0



Domain of the equation: 3(18y-6)!=0

y∈R





Domain of the equation: 6(12-4y))!=0

y∈R



We add all the numbers together, and all the variables

1/3(18y-6)-(-5/6(-4y+12))=0

We calculate fractions


(6y(-)/(3(18y-6)*6(-4y+12)))+(-(-15y1)/(3(18y-6)*6(-4y+12)))=0



We calculate terms in parentheses: +(6y(-)/(3(18y-6)*6(-4y+12))), so:

6y(-)/(3(18y-6)*6(-4y+12))

We add all the numbers together, and all the variables

6y0/(3(18y-6)*6(-4y+12))

We multiply all the terms by the denominator


6y0

We add all the numbers together, and all the variables

6y

Back to the equation:

+(6y)





We calculate terms in parentheses: +(-(-15y1)/(3(18y-6)*6(-4y+12))), so:

-(-15y1)/(3(18y-6)*6(-4y+12))

We add all the numbers together, and all the variables

-(-15y)/(3(18y-6)*6(-4y+12))

We multiply all the terms by the denominator


-(-15y)

We get rid of parentheses

15y

Back to the equation:

+(15y)



We add all the numbers together, and all the variables

21y=0

y=0/21

y=0

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