1/3(2+-3a)=6-a

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Solution for 1/3(2+-3a)=6-a equation: 



1/3(2+-3a)=6-a

We move all terms to the left:

1/3(2+-3a)-(6-a)=0



Domain of the equation: 3(2+-3a)!=0

a∈R



We add all the numbers together, and all the variables

1/3(-3a)-(-1a+6)=0

We get rid of parentheses

1/3(-3a)+1a-6=0

We multiply all the terms by the denominator


1a*3(-3a)-6*3(-3a)+1=0

Wy multiply elements

3a^2(--18a(-+1=0

We use the square of the difference formula

3a^2(+18a(-1=0

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