1/3(21-3x)=1/8(8-4x)

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Solution for 1/3(21-3x)=1/8(8-4x) equation: 



1/3(21-3x)=1/8(8-4x)

We move all terms to the left:

1/3(21-3x)-(1/8(8-4x))=0



Domain of the equation: 3(21-3x)!=0

x∈R





Domain of the equation: 8(8-4x))!=0

x∈R



We add all the numbers together, and all the variables

1/3(-3x+21)-(1/8(-4x+8))=0

We calculate fractions


(8x(-)/(3(-3x+21)*8(-4x+8)))+(-3x0/(3(-3x+21)*8(-4x+8)))=0



We calculate terms in parentheses: +(8x(-)/(3(-3x+21)*8(-4x+8))), so:

8x(-)/(3(-3x+21)*8(-4x+8))

We add all the numbers together, and all the variables

8x0/(3(-3x+21)*8(-4x+8))

We multiply all the terms by the denominator


8x0

We add all the numbers together, and all the variables

8x

Back to the equation:

+(8x)





We calculate terms in parentheses: +(-3x0/(3(-3x+21)*8(-4x+8))), so:

-3x0/(3(-3x+21)*8(-4x+8))

We multiply all the terms by the denominator


-3x0

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

8x-3x=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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