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1/3(25-5k=21-3(k-4)
We move all terms to the left:
1/3(25-5k-(21-3(k-4))=0
Domain of the equation: 3(25-5k-(21-3(k-4))!=0We multiply all the terms by the denominator
k∈R
1!=0
There is no solution for this equation
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