1/3(26x-169)=1/12(-156+24x)

Solution for 1/3(26x-169)=1/12(-156+24x) equation:

1/3(26x-169)=1/12(-156+24x)

We move all terms to the left:

1/3(26x-169)-(1/12(-156+24x))=0


Domain of the equation: 3(26x-169)!=0

x∈R



Domain of the equation: 12(-156+24x))!=0

x∈R


We add all the numbers together, and all the variables

1/3(26x-169)-(1/12(24x-156))=0

We calculate fractions


(12x2/(3(26x-169)*12(24x-156)))+(-3x2/(3(26x-169)*12(24x-156)))=0


We calculate terms in parentheses: +(12x2/(3(26x-169)*12(24x-156))), so:

12x2/(3(26x-169)*12(24x-156))

We multiply all the terms by the denominator


12x2

We add all the numbers together, and all the variables

12x^2

Back to the equation:

+(12x^2)



We calculate terms in parentheses: +(-3x2/(3(26x-169)*12(24x-156))), so:

-3x2/(3(26x-169)*12(24x-156))

We multiply all the terms by the denominator


-3x2

We add all the numbers together, and all the variables

-3x^2

Back to the equation:

+(-3x^2)


We add all the numbers together, and all the variables

12x^2+(-3x^2)=0

We get rid of parentheses

12x^2-3x^2=0

We add all the numbers together, and all the variables

9x^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{18}=0$