1/3(26x-169)=1/2(-156+24x)

Solution for 1/3(26x-169)=1/2(-156+24x) equation:

1/3(26x-169)=1/2(-156+24x)

We move all terms to the left:

1/3(26x-169)-(1/2(-156+24x))=0


Domain of the equation: 3(26x-169)!=0

x∈R



Domain of the equation: 2(-156+24x))!=0

x∈R


We add all the numbers together, and all the variables

1/3(26x-169)-(1/2(24x-156))=0

We calculate fractions


(2x2/(3(26x-169)*2(24x-156)))+(-3x2/(3(26x-169)*2(24x-156)))=0


We calculate terms in parentheses: +(2x2/(3(26x-169)*2(24x-156))), so:

2x2/(3(26x-169)*2(24x-156))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)



We calculate terms in parentheses: +(-3x2/(3(26x-169)*2(24x-156))), so:

-3x2/(3(26x-169)*2(24x-156))

We multiply all the terms by the denominator


-3x2

We add all the numbers together, and all the variables

-3x^2

Back to the equation:

+(-3x^2)


We add all the numbers together, and all the variables

2x^2+(-3x^2)=0

We get rid of parentheses

2x^2-3x^2=0

We add all the numbers together, and all the variables

-1x^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-2}=0$