1/3(27x-12)-10x=6x+3-2x

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Solution for 1/3(27x-12)-10x=6x+3-2x equation: 



1/3(27x-12)-10x=6x+3-2x

We move all terms to the left:

1/3(27x-12)-10x-(6x+3-2x)=0



Domain of the equation: 3(27x-12)!=0

x∈R



We add all the numbers together, and all the variables

1/3(27x-12)-10x-(4x+3)=0

We add all the numbers together, and all the variables

-10x+1/3(27x-12)-(4x+3)=0

We get rid of parentheses

-10x+1/3(27x-12)-4x-3=0

We multiply all the terms by the denominator


-10x*3(27x-12)-4x*3(27x-12)-3*3(27x-12)+1=0

Wy multiply elements

-30x^2(2-12x^2(2-9x(2+1=0

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