1/3(27x-33)+1=5(3x-2)-2(33

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Solution for 1/3(27x-33)+1=5(3x-2)-2(33 equation: 



1/3(27x-33)+1=5(3x-2)-2(33

We move all terms to the left:

1/3(27x-33)+1-(5(3x-2)-2(33)=0



Domain of the equation: 3(27x-33)!=0

x∈R



We multiply all the terms by the denominator


-((5(3x-2)-233+1)*3(27x-33)+1=0

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