1/3(27y-360)=40+5y

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Solution for 1/3(27y-360)=40+5y equation: 



1/3(27y-360)=40+5y

We move all terms to the left:

1/3(27y-360)-(40+5y)=0



Domain of the equation: 3(27y-360)!=0

y∈R



We add all the numbers together, and all the variables

1/3(27y-360)-(5y+40)=0

We get rid of parentheses

1/3(27y-360)-5y-40=0

We multiply all the terms by the denominator


-5y*3(27y-360)-40*3(27y-360)+1=0

Wy multiply elements

-15y^2(2-120y(2+1=0

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