1/3(2b+9)=2/3(b=9/2)

Solution for 1/3(2b+9)=2/3(b=9/2) equation:

1/3(2b+9)=2/3(b=9/2)

We move all terms to the left:

1/3(2b+9)-(2/3(b)=0


Domain of the equation: 3(2b+9)!=0

b∈R



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R


We calculate fractions


3b/(18b^2+81b)+(-6b2/(18b^2+81b)=0


We calculate terms in parentheses: +(-6b2/(18b^2+81b), so:

-6b2/(18b^2+81b

We multiply all the terms by the denominator


-6b2

We add all the numbers together, and all the variables

-6b^2

Back to the equation:

+(-6b^2)


We get rid of parentheses

-6b^2+3b/(18b^2+81b)=0

We multiply all the terms by the denominator


-6b^2*(18b^2+81b)+3b=0