1/3(2m-10)=2/3m+10

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Solution for 1/3(2m-10)=2/3m+10 equation: 


m in (-oo:+oo)

(1/3)*(2*m-10) = (2/3)*m+10 // - (2/3)*m+10

(1/3)*(2*m-10)-((2/3)*m)-10 = 0

(1/3)*(2*m-10)+(-2/3)*m-10 = 0

1/3*(2*m-10)+(-2*m)/3-10 = 0

(1/3*3*(2*m-10))/3+(-2*m)/3+(-10*3)/3 = 0

1/3*3*(2*m-10)-2*m-10*3 = 0

-30-10 = 0

-40 = 0

-40/3 = 0

-40/3 = 0 // * 3

-40 = 0

m belongs to the empty set

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