1/3(2m-16)=1/3(2m+4)

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Solution for 1/3(2m-16)=1/3(2m+4) equation: 



1/3(2m-16)=1/3(2m+4)

We move all terms to the left:

1/3(2m-16)-(1/3(2m+4))=0



Domain of the equation: 3(2m-16)!=0

m∈R





Domain of the equation: 3(2m+4))!=0

m∈R



We calculate fractions


(3m2/(3(2m-16)*3(2m+4)))+(-3m2/(3(2m-16)*3(2m+4)))=0



We calculate terms in parentheses: +(3m2/(3(2m-16)*3(2m+4))), so:

3m2/(3(2m-16)*3(2m+4))

We multiply all the terms by the denominator


3m2

We add all the numbers together, and all the variables

3m^2

Back to the equation:

+(3m^2)





We calculate terms in parentheses: +(-3m2/(3(2m-16)*3(2m+4))), so:

-3m2/(3(2m-16)*3(2m+4))

We multiply all the terms by the denominator


-3m2

We add all the numbers together, and all the variables

-3m^2

Back to the equation:

+(-3m^2)



We add all the numbers together, and all the variables

3m^2+(-3m^2)=0

We get rid of parentheses

3m^2-3m^2=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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