1/3(2x+6)=-7-1/3(x+9)

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Solution for 1/3(2x+6)=-7-1/3(x+9) equation: 



1/3(2x+6)=-7-1/3(x+9)

We move all terms to the left:

1/3(2x+6)-(-7-1/3(x+9))=0



Domain of the equation: 3(2x+6)!=0

x∈R





Domain of the equation: 3(x+9))!=0

x∈R



We calculate fractions


(3xx/(3(2x+6)*3(x+9)))+(-(-3x2)/(3(2x+6)*3(x+9)))=0



We calculate terms in parentheses: +(3xx/(3(2x+6)*3(x+9))), so:

3xx/(3(2x+6)*3(x+9))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-(-3x2)/(3(2x+6)*3(x+9))), so:

-(-3x2)/(3(2x+6)*3(x+9))

We add all the numbers together, and all the variables

-(-3x^2)/(3(2x+6)*3(x+9))

We multiply all the terms by the denominator


-(-3x^2)

We get rid of parentheses

3x^2

Back to the equation:

+(3x^2)



determiningTheFunctionDomain
3x^2+3xx=0

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