1/3(2x+6)=2/5(x-10)

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Solution for 1/3(2x+6)=2/5(x-10) equation: 



1/3(2x+6)=2/5(x-10)

We move all terms to the left:

1/3(2x+6)-(2/5(x-10))=0



Domain of the equation: 3(2x+6)!=0

x∈R





Domain of the equation: 5(x-10))!=0

x∈R



We calculate fractions


(5xx/(3(2x+6)*5(x-10)))+(-6x2/(3(2x+6)*5(x-10)))=0



We calculate terms in parentheses: +(5xx/(3(2x+6)*5(x-10))), so:

5xx/(3(2x+6)*5(x-10))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)





We calculate terms in parentheses: +(-6x2/(3(2x+6)*5(x-10))), so:

-6x2/(3(2x+6)*5(x-10))

We multiply all the terms by the denominator


-6x2

We add all the numbers together, and all the variables

-6x^2

Back to the equation:

+(-6x^2)



We get rid of parentheses

-6x^2+5xx=0

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