1/3(2x+7)=1/2(x+3)

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Solution for 1/3(2x+7)=1/2(x+3) equation:



1/3(2x+7)=1/2(x+3)
We move all terms to the left:
1/3(2x+7)-(1/2(x+3))=0
Domain of the equation: 3(2x+7)!=0
x∈R
Domain of the equation: 2(x+3))!=0
x∈R
We calculate fractions
(2xx/(3(2x+7)*2(x+3)))+(-3x2/(3(2x+7)*2(x+3)))=0
We calculate terms in parentheses: +(2xx/(3(2x+7)*2(x+3))), so:
2xx/(3(2x+7)*2(x+3))
We multiply all the terms by the denominator
2xx
Back to the equation:
+(2xx)
We calculate terms in parentheses: +(-3x2/(3(2x+7)*2(x+3))), so:
-3x2/(3(2x+7)*2(x+3))
We multiply all the terms by the denominator
-3x2
We add all the numbers together, and all the variables
-3x^2
Back to the equation:
+(-3x^2)
We get rid of parentheses
-3x^2+2xx=0

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