1/3(2x+9)=2/3x

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Solution for 1/3(2x+9)=2/3x equation: 


x in (-oo:+oo)

(1/3)*(2*x+9) = (2/3)*x // - (2/3)*x

(1/3)*(2*x+9)-((2/3)*x) = 0

(1/3)*(2*x+9)+(-2/3)*x = 0

1/3*(2*x+9)+(-2*x)/3 = 0

(1/3*3*(2*x+9))/3+(-2*x)/3 = 0

1/3*3*(2*x+9)-2*x = 0

9 = 0

9/3 = 0

9/3 = 0 // * 3

9 = 0

x belongs to the empty set

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