1/3(2x-1)=4(x/6+2)

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Solution for 1/3(2x-1)=4(x/6+2) equation: 


x in (-oo:+oo)

(1/3)*(2*x-1) = 4*(x/6+2) // - 4*(x/6+2)

(1/3)*(2*x-1)-(4*(x/6+2)) = 0

(1/3)*(2*x-1)-4*(x/6+2) = 0

1/3*(2*x-1)-4*(1/6*x+2) = 0

1/3*(2*x-1)-4*(1/6*x+2) = 0

-25/3 = 0

-25/3 = 0

-25/3 = 0 // * 3

-25 = 0

x belongs to the empty set

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