1/3(2x-4)+5=2/3(x-1)

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Solution for 1/3(2x-4)+5=2/3(x-1) equation:



1/3(2x-4)+5=2/3(x-1)
We move all terms to the left:
1/3(2x-4)+5-(2/3(x-1))=0
Domain of the equation: 3(2x-4)!=0
x∈R
Domain of the equation: 3(x-1))!=0
x∈R
We calculate fractions
(3xx/(3(2x-4)*3(x-1)))+(-6x2/(3(2x-4)*3(x-1)))+5=0
We calculate terms in parentheses: +(3xx/(3(2x-4)*3(x-1))), so:
3xx/(3(2x-4)*3(x-1))
We multiply all the terms by the denominator
3xx
Back to the equation:
+(3xx)
We calculate terms in parentheses: +(-6x2/(3(2x-4)*3(x-1))), so:
-6x2/(3(2x-4)*3(x-1))
We multiply all the terms by the denominator
-6x2
We add all the numbers together, and all the variables
-6x^2
Back to the equation:
+(-6x^2)
We get rid of parentheses
-6x^2+3xx+5=0
We move all terms containing x to the left, all other terms to the right
-6x^2+3xx=-5

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