1/3(2x-5)=25+3x-6

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Solution for 1/3(2x-5)=25+3x-6 equation: 



1/3(2x-5)=25+3x-6

We move all terms to the left:

1/3(2x-5)-(25+3x-6)=0



Domain of the equation: 3(2x-5)!=0

x∈R



We add all the numbers together, and all the variables

1/3(2x-5)-(3x+19)=0

We get rid of parentheses

1/3(2x-5)-3x-19=0

We multiply all the terms by the denominator


-3x*3(2x-5)-19*3(2x-5)+1=0

Wy multiply elements

-9x^2(2-57x(2+1=0

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