1/3(2y-2)+1/6(8y+6)

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Solution for 1/3(2y-2)+1/6(8y+6) equation: 


y in (-oo:+oo)

(1/3)*(2*y-2)+(1/6)*(8*y+6) = 0

1/3*(2*y-2)+1/6*(8*y+6) = 0

1/3*(2*y-2)+1/6*(8*y+6) = 0

2*y+1/3 = 0

2*y+1/3 = 0

2*y+1/3 = 0 // - 1/3

2*y = -1/3 // : 2

y = -1/3/2

y = -1/6

y = -1/6

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