1/3(3+9r)=7/4(28-12r)

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Solution for 1/3(3+9r)=7/4(28-12r) equation: 


r in (-oo:+oo)

(1/3)*(9*r+3) = (7/4)*(28-(12*r)) // - (7/4)*(28-(12*r))

(1/3)*(9*r+3)-((7/4)*(28-(12*r))) = 0

(1/3)*(9*r+3)+(-7/4)*(28-12*r) = 0

1/3*(9*r+3)-7/4*(28-12*r) = 0

1/3*(9*r+3)-7/4*(28-12*r) = 0

24*r-48 = 0

24*r-48 = 0

24*r-48 = 0 // + 48

24*r = 48 // : 24

r = 48/24

r = 2

r = 2

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