1/3(3+9x)=7/4(28-12x)

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Solution for 1/3(3+9x)=7/4(28-12x) equation: 


x in (-oo:+oo)

(1/3)*(9*x+3) = (7/4)*(28-(12*x)) // - (7/4)*(28-(12*x))

(1/3)*(9*x+3)-((7/4)*(28-(12*x))) = 0

(1/3)*(9*x+3)+(-7/4)*(28-12*x) = 0

1/3*(9*x+3)-7/4*(28-12*x) = 0

1/3*(9*x+3)-7/4*(28-12*x) = 0

24*x-48 = 0

24*x-48 = 0

24*x-48 = 0 // + 48

24*x = 48 // : 24

x = 48/24

x = 2

x = 2

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