1/3(3-2x)=-4(x+1)

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Solution for 1/3(3-2x)=-4(x+1) equation: 



1/3(3-2x)=-4(x+1)

We move all terms to the left:

1/3(3-2x)-(-4(x+1))=0



Domain of the equation: 3(3-2x)!=0

x∈R



We add all the numbers together, and all the variables

1/3(-2x+3)-(-4(x+1))=0

We multiply all the terms by the denominator


-((-4(x+1)))*3(-2x+3)+1=0



We calculate terms in parentheses: -((-4(x+1)))*3(-2x+3), so:

(-4(x+1)))*3(-2x+3

We add all the numbers together, and all the variables

-2x+(-4(x+1)))*3(+3

Back to the equation:

-(-2x+(-4(x+1)))*3(+3)



We add all the numbers together, and all the variables

-(-2x+(-4(x+1)))*33+1=0

We move all terms containing x to the left, all other terms to the right

-(-2x+(-4(x+1)))*33=-1

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