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1/3(3-6x)=-3(8x-4)
We move all terms to the left:
1/3(3-6x)-(-3(8x-4))=0
Domain of the equation: 3(3-6x)!=0We add all the numbers together, and all the variables
x∈R
1/3(-6x+3)-(-3(8x-4))=0
We multiply all the terms by the denominator
-((-3(8x-4)))*3(-6x+3)+1=0
We calculate terms in parentheses: -((-3(8x-4)))*3(-6x+3), so:We add all the numbers together, and all the variables
(-3(8x-4)))*3(-6x+3
We add all the numbers together, and all the variables
-6x+(-3(8x-4)))*3(+3
Back to the equation:
-(-6x+(-3(8x-4)))*3(+3)
-(-6x+(-3(8x-4)))*33+1=0
We move all terms containing x to the left, all other terms to the right
-(-6x+(-3(8x-4)))*33=-1
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