1/3(3-z)=1-1/3z

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Solution for 1/3(3-z)=1-1/3z equation: 



1/3(3-z)=1-1/3z

We move all terms to the left:

1/3(3-z)-(1-1/3z)=0



Domain of the equation: 3(3-z)!=0

z∈R





Domain of the equation: 3z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

1/3(-1z+3)-(-1/3z+1)=0

We get rid of parentheses

1/3(-1z+3)+1/3z-1=0

We calculate fractions


3z/(-9z^2+27z)+(3z(-)/(-9z^2+27z)-1=0

We add all the numbers together, and all the variables

3z/(-9z^2+27z)+(3z0/(-9z^2+27z)-1=0

We calculate fractions

We do not support ezpression: z^3

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