1/3(3-z)=3

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Solution for 1/3(3-z)=3 equation: 



1/3(3-z)=3

We move all terms to the left:

1/3(3-z)-(3)=0



Domain of the equation: 3(3-z)!=0

z∈R



We add all the numbers together, and all the variables

1/3(-1z+3)-3=0

We multiply all the terms by the denominator


-3*3(-1z+3)+1=0

Wy multiply elements

-9z(-+1=0

We use the square of the difference formula

-9z(-1=0

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