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1/3(3m-6)-1/4(5m+4)+1/5(2m-9=-3
We move all terms to the left:
1/3(3m-6)-1/4(5m+4)+1/5(2m-9-(-3)=0
Domain of the equation: 3(3m-6)!=0
m∈R
Domain of the equation: 4(5m+4)!=0
m∈R
Domain of the equation: 5(2m-9-(-3)!=0We calculate fractions
m∈R
(20m^25/(3(3m-6)*4(5m+4)*5(2m-9-(-3))+(-15m^23/(3(3m-6)*4(5m+4)*5(2m-9-(-3))+(12m^23/(3(3m-6)*4(5m+4)*5(2m-9-(-3))=0
We calculate terms in parentheses: +(20m^25/(3(3m-6)*4(5m+4)*5(2m-9-(-3))+(-15m^23/(3(3m-6)*4(5m+4)*5(2m-9-(-3))+(12m^23/(3(3m-6)*4(5m+4)*5(2m-9-(-3)), so:
20m^25/(3(3m-6)*4(5m+4)*5(2m-9-(-3))+(-15m^23/(3(3m-6)*4(5m+4)*5(2m-9-(-3))+(12m^23/(3(3m-6)*4(5m+4)*5(2m-9-(-3)
We do not support empression: m^25
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