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1/3(3n+9)=5n-12-n
We move all terms to the left:
1/3(3n+9)-(5n-12-n)=0
Domain of the equation: 3(3n+9)!=0We add all the numbers together, and all the variables
n∈R
1/3(3n+9)-(4n-12)=0
We get rid of parentheses
1/3(3n+9)-4n+12=0
We multiply all the terms by the denominator
-4n*3(3n+9)+12*3(3n+9)+1=0
Wy multiply elements
-12n^2(3+36n(3+1=0
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