1/3(3t+12)-2t=-(t+8)

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Solution for 1/3(3t+12)-2t=-(t+8) equation: 



1/3(3t+12)-2t=-(t+8)

We move all terms to the left:

1/3(3t+12)-2t-(-(t+8))=0



Domain of the equation: 3(3t+12)!=0

t∈R



We add all the numbers together, and all the variables

-2t+1/3(3t+12)-(-(t+8))=0

We multiply all the terms by the denominator


-2t*3(3t+12)-((-(t+8)))*3(3t+12)+1=0



We calculate terms in parentheses: -((-(t+8)))*3(3t+12), so:

(-(t+8)))*3(3t+12



Wy multiply elements

-6t^2(3-((-(t+8)))*3(3t+12)+1=0

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