1/3(3w-6)=1/2(2w-4)

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Solution for 1/3(3w-6)=1/2(2w-4) equation:



1/3(3w-6)=1/2(2w-4)
We move all terms to the left:
1/3(3w-6)-(1/2(2w-4))=0
Domain of the equation: 3(3w-6)!=0
w∈R
Domain of the equation: 2(2w-4))!=0
w∈R
We calculate fractions
(2w2/(3(3w-6)*2(2w-4)))+(-3w3/(3(3w-6)*2(2w-4)))=0
We calculate terms in parentheses: +(2w2/(3(3w-6)*2(2w-4))), so:
2w2/(3(3w-6)*2(2w-4))
We multiply all the terms by the denominator
2w2
We add all the numbers together, and all the variables
2w^2
Back to the equation:
+(2w^2)
We calculate terms in parentheses: +(-3w3/(3(3w-6)*2(2w-4))), so:
-3w3/(3(3w-6)*2(2w-4))
We multiply all the terms by the denominator
-3w3
We add all the numbers together, and all the variables
-3w^3
We do not support ewpression: w^3

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