1/3(3x+12)+3x=2(5x-4)

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Solution for 1/3(3x+12)+3x=2(5x-4) equation:



1/3(3x+12)+3x=2(5x-4)
We move all terms to the left:
1/3(3x+12)+3x-(2(5x-4))=0
Domain of the equation: 3(3x+12)!=0
x∈R
We add all the numbers together, and all the variables
3x+1/3(3x+12)-(2(5x-4))=0
We multiply all the terms by the denominator
3x*3(3x+12)-((2(5x-4)))*3(3x+12)+1=0
We calculate terms in parentheses: -((2(5x-4)))*3(3x+12), so:
(2(5x-4)))*3(3x+12
Wy multiply elements
9x^2(3-((2(5x-4)))*3(3x+12)+1=0

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