1/3(3x-12)=1/4(8x+20)

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Solution for 1/3(3x-12)=1/4(8x+20) equation: 



1/3(3x-12)=1/4(8x+20)

We move all terms to the left:

1/3(3x-12)-(1/4(8x+20))=0



Domain of the equation: 3(3x-12)!=0

x∈R





Domain of the equation: 4(8x+20))!=0

x∈R



We calculate fractions


(4x8/(3(3x-12)*4(8x+20)))+(-3x3/(3(3x-12)*4(8x+20)))=0



We calculate terms in parentheses: +(4x8/(3(3x-12)*4(8x+20))), so:

4x8/(3(3x-12)*4(8x+20))

We multiply all the terms by the denominator


4x8

We add all the numbers together, and all the variables

4x^8

We do not support expression: x^8

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