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(1/3)*(3*x-6)-(6*x) = 4-5*x // - 4-5*x
(1/3)*(3*x-6)-(6*x)-(-5*x)-4 = 0
(1/3)*(3*x-6)-6*x+5*x-4 = 0
1/3*(3*x-6)-6*x+5*x-4 = 0
1/3*(3*x-6)-6*x+5*x-4 = 0
5*x-5*x-4-2 = 0
-4-2 = 0
-6 = 0
-6 = 0
x belongs to the empty set
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