1/3(3x-6)=-1/2(2x-4)

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Solution for 1/3(3x-6)=-1/2(2x-4) equation:



1/3(3x-6)=-1/2(2x-4)
We move all terms to the left:
1/3(3x-6)-(-1/2(2x-4))=0
Domain of the equation: 3(3x-6)!=0
x∈R
Domain of the equation: 2(2x-4))!=0
x∈R
We calculate fractions
(2x2/(3(3x-6)*2(2x-4)))+(-(-3x3)/(3(3x-6)*2(2x-4)))=0
We calculate terms in parentheses: +(2x2/(3(3x-6)*2(2x-4))), so:
2x2/(3(3x-6)*2(2x-4))
We multiply all the terms by the denominator
2x2
We add all the numbers together, and all the variables
2x^2
Back to the equation:
+(2x^2)
We calculate terms in parentheses: +(-(-3x3)/(3(3x-6)*2(2x-4))), so:
-(-3x3)/(3(3x-6)*2(2x-4))
We add all the numbers together, and all the variables
-(-3x^3)/(3(3x-6)*2(2x-4))
We multiply all the terms by the denominator
-(-3x^3)
We do not support expression: x^3

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