1/3(3x-9)=1/4(4x+12)

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Solution for 1/3(3x-9)=1/4(4x+12) equation: 



1/3(3x-9)=1/4(4x+12)

We move all terms to the left:

1/3(3x-9)-(1/4(4x+12))=0



Domain of the equation: 3(3x-9)!=0

x∈R





Domain of the equation: 4(4x+12))!=0

x∈R



We calculate fractions


(4x4/(3(3x-9)*4(4x+12)))+(-3x3/(3(3x-9)*4(4x+12)))=0



We calculate terms in parentheses: +(4x4/(3(3x-9)*4(4x+12))), so:

4x4/(3(3x-9)*4(4x+12))

We multiply all the terms by the denominator


4x4

We add all the numbers together, and all the variables

4x^4

We do not support expression: x^4

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