1/3(3y+12)-6=1/2(4y-14)

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Solution for 1/3(3y+12)-6=1/2(4y-14) equation: 



1/3(3y+12)-6=1/2(4y-14)

We move all terms to the left:

1/3(3y+12)-6-(1/2(4y-14))=0



Domain of the equation: 3(3y+12)!=0

y∈R





Domain of the equation: 2(4y-14))!=0

y∈R



We calculate fractions


(2y4/(3(3y+12)*2(4y-14)))+(-3y3/(3(3y+12)*2(4y-14)))-6=0



We calculate terms in parentheses: +(2y4/(3(3y+12)*2(4y-14))), so:

2y4/(3(3y+12)*2(4y-14))

We multiply all the terms by the denominator


2y4

We add all the numbers together, and all the variables

2y^4

We do not support eypression: y^4

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