1/3(3y+6)-8=-1/9(27y-54)

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Solution for 1/3(3y+6)-8=-1/9(27y-54) equation: 



1/3(3y+6)-8=-1/9(27y-54)

We move all terms to the left:

1/3(3y+6)-8-(-1/9(27y-54))=0



Domain of the equation: 3(3y+6)!=0

y∈R





Domain of the equation: 9(27y-54))!=0

y∈R



We calculate fractions


(9y2/(3(3y+6)*9(27y-54)))+(-(-3y3)/(3(3y+6)*9(27y-54)))-8=0



We calculate terms in parentheses: +(9y2/(3(3y+6)*9(27y-54))), so:

9y2/(3(3y+6)*9(27y-54))

We multiply all the terms by the denominator


9y2

We add all the numbers together, and all the variables

9y^2

Back to the equation:

+(9y^2)





We calculate terms in parentheses: +(-(-3y3)/(3(3y+6)*9(27y-54))), so:

-(-3y3)/(3(3y+6)*9(27y-54))

We add all the numbers together, and all the variables

-(-3y^3)/(3(3y+6)*9(27y-54))

We multiply all the terms by the denominator


-(-3y^3)

We do not support eypression: y^3

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