1/3(3y-12)+4=y

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Solution for 1/3(3y-12)+4=y equation: 



1/3(3y-12)+4=y

We move all terms to the left:

1/3(3y-12)+4-(y)=0



Domain of the equation: 3(3y-12)!=0

y∈R



We add all the numbers together, and all the variables

-1y+1/3(3y-12)+4=0

We multiply all the terms by the denominator


-1y*3(3y-12)+4*3(3y-12)+1=0

Wy multiply elements

-3y^2(3+12y(3+1=0

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