1/3(3z+12)=16

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Solution for 1/3(3z+12)=16 equation: 



1/3(3z+12)=16

We move all terms to the left:

1/3(3z+12)-(16)=0



Domain of the equation: 3(3z+12)!=0

z∈R



We multiply all the terms by the denominator


-16*3(3z+12)+1=0

Wy multiply elements

-48z(3+1=0

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