1/3(4-2h)=-1/4(h+2)

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Solution for 1/3(4-2h)=-1/4(h+2) equation: 



1/3(4-2h)=-1/4(h+2)

We move all terms to the left:

1/3(4-2h)-(-1/4(h+2))=0



Domain of the equation: 3(4-2h)!=0

h∈R





Domain of the equation: 4(h+2))!=0

h∈R



We add all the numbers together, and all the variables

1/3(-2h+4)-(-1/4(h+2))=0

We calculate fractions


(4hh/(3(-2h+4)*4(h+2)))+(-(-3h0)/(3(-2h+4)*4(h+2)))=0



We calculate terms in parentheses: +(4hh/(3(-2h+4)*4(h+2))), so:

4hh/(3(-2h+4)*4(h+2))

We multiply all the terms by the denominator


4hh

Back to the equation:

+(4hh)





We calculate terms in parentheses: +(-(-3h0)/(3(-2h+4)*4(h+2))), so:

-(-3h0)/(3(-2h+4)*4(h+2))

We add all the numbers together, and all the variables

-(-3h)/(3(-2h+4)*4(h+2))

We multiply all the terms by the denominator


-(-3h)

We get rid of parentheses

3h

Back to the equation:

+(3h)



We add all the numbers together, and all the variables

3h+4hh=0

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