1/3(49k+7)=7k-1

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Solution for 1/3(49k+7)=7k-1 equation: 



1/3(49k+7)=7k-1

We move all terms to the left:

1/3(49k+7)-(7k-1)=0



Domain of the equation: 3(49k+7)!=0

k∈R



We get rid of parentheses

1/3(49k+7)-7k+1=0

We multiply all the terms by the denominator


-7k*3(49k+7)+1*3(49k+7)+1=0

Wy multiply elements

-21k^2(4+3k(4+1=0

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