1/3(4a+1)=1/2(a)

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Solution for 1/3(4a+1)=1/2(a) equation: 



1/3(4a+1)=1/2(a)

We move all terms to the left:

1/3(4a+1)-(1/2(a))=0



Domain of the equation: 3(4a+1)!=0

a∈R





Domain of the equation: 2a)!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

1/3(4a+1)-(+1/2a)=0

We get rid of parentheses

1/3(4a+1)-1/2a=0

We calculate fractions


2a/(24a^2+6a)+(-3a4/(24a^2+6a)=0



We calculate terms in parentheses: +(-3a4/(24a^2+6a), so:

-3a4/(24a^2+6a

We multiply all the terms by the denominator


-3a4

We add all the numbers together, and all the variables

-3a^4

We do not support eapression: a^4

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