1/3(4x+1)=1/2x

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Solution for 1/3(4x+1)=1/2x equation: 



1/3(4x+1)=1/2x

We move all terms to the left:

1/3(4x+1)-(1/2x)=0



Domain of the equation: 3(4x+1)!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/3(4x+1)-(+1/2x)=0

We get rid of parentheses

1/3(4x+1)-1/2x=0

We calculate fractions


2x/(24x^2+6x)+(-3x4/(24x^2+6x)=0



We calculate terms in parentheses: +(-3x4/(24x^2+6x), so:

-3x4/(24x^2+6x

We multiply all the terms by the denominator


-3x4

We add all the numbers together, and all the variables

-3x^4

We do not support expression: x^4

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