1/3(4x+1)=3(3-4x)+18

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Solution for 1/3(4x+1)=3(3-4x)+18 equation: 


x in (-oo:+oo)

(1/3)*(4*x+1) = 3*(3-(4*x))+18 // - 3*(3-(4*x))+18

(1/3)*(4*x+1)-(3*(3-(4*x)))-18 = 0

(1/3)*(4*x+1)-3*(3-4*x)-18 = 0

1/3*(4*x+1)-3*(3-4*x)-18 = 0

1/3*(4*x+1)-3*(3-4*x)-18 = 0

40/3*x-18-26/3 = 0

40/3*x-80/3 = 0

40/3*x-80/3 = 0

40/3*x-80/3 = 0 // + 80/3

40/3*x = 80/3 // : 40/3

x = 80/3/40/3

x = 2

x = 2

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