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1/3(4x+5)-2/3=1/9(3x+18)
We move all terms to the left:
1/3(4x+5)-2/3-(1/9(3x+18))=0
Domain of the equation: 3(4x+5)!=0
x∈R
Domain of the equation: 9(3x+18))!=0We calculate fractions
x∈R
(9x3/(3(4x+5)*9(3x+18))*3)+(-(1*3(4x+5)*3)/(3(4x+5)*9(3x+18))*3)+(-18x3/(3(4x+5)*9(3x+18))*3)=0
We calculate terms in parentheses: +(9x3/(3(4x+5)*9(3x+18))*3), so:
9x3/(3(4x+5)*9(3x+18))*3
We multiply all the terms by the denominator
9x3
We add all the numbers together, and all the variables
9x^3
We do not support expression: x^3
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