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1/3(4x-1)+2/5(2x+5)-514/5=0
Domain of the equation: 3(4x-1)!=0
x∈R
Domain of the equation: 5(2x+5)!=0We calculate fractions
x∈R
(25x2/(3(4x-1)*5(2x+5)*5)+(6x4/(3(4x-1)*5(2x+5)*5)+(-1542x4/(3(4x-1)*5(2x+5)*5)=0
We calculate terms in parentheses: +(25x2/(3(4x-1)*5(2x+5)*5)+(6x4/(3(4x-1)*5(2x+5)*5)+(-1542x4/(3(4x-1)*5(2x+5)*5), so:
25x2/(3(4x-1)*5(2x+5)*5)+(6x4/(3(4x-1)*5(2x+5)*5)+(-1542x4/(3(4x-1)*5(2x+5)*5
We can not solve this equation
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