1/3(4x-7x)-6x=14

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Solution for 1/3(4x-7x)-6x=14 equation: 



1/3(4x-7x)-6x=14

We move all terms to the left:

1/3(4x-7x)-6x-(14)=0



Domain of the equation: 3(4x-7x)!=0

x∈R



We add all the numbers together, and all the variables

1/3(-3x)-6x-14=0

We add all the numbers together, and all the variables

-6x+1/3(-3x)-14=0

We multiply all the terms by the denominator


-6x*3(-3x)-14*3(-3x)+1=0

Wy multiply elements

-18x^2(--42x(-+1=0

We use the square of the difference formula

-18x^2(+42x(-1=0

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