1/3(4x-8)=1/2(2x-7)

Solution for 1/3(4x-8)=1/2(2x-7) equation:

1/3(4x-8)=1/2(2x-7)

We move all terms to the left:

1/3(4x-8)-(1/2(2x-7))=0


Domain of the equation: 3(4x-8)!=0

x∈R



Domain of the equation: 2(2x-7))!=0

x∈R


We calculate fractions


(2x2/(3(4x-8)*2(2x-7)))+(-3x4/(3(4x-8)*2(2x-7)))=0


We calculate terms in parentheses: +(2x2/(3(4x-8)*2(2x-7))), so:

2x2/(3(4x-8)*2(2x-7))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)



We calculate terms in parentheses: +(-3x4/(3(4x-8)*2(2x-7))), so:

-3x4/(3(4x-8)*2(2x-7))

We multiply all the terms by the denominator


-3x4

We add all the numbers together, and all the variables

-3x^4

We do not support expression: x^4